16x^2+3=7

Solution for 16x^2+3=7 equation:

16x^2+3=7

We move all terms to the left:

16x^2+3-(7)=0

We add all the numbers together, and all the variables

16x^2-4=0

a = 16; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·16·(-4)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*16}=\frac{-16}{32}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*16}=\frac{16}{32}
=1/2
$